15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
<h3>What is a permutation?</h3>
A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.
Now, 
= 13!/(13-5)!
= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444
Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
To learn more about the permutation visit:
brainly.com/question/1216161.
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it depends how long the width and the length is. If the length is 5 cm and the width is 4 cm the perimeter will be 18cm. All you have to do is 5 doubled because there 2 sides for the length and 4 doubled because there are 2 sides for the width. I hope I have answered your question. XD
Answer:
C=10
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.
3/2c+23-23=38-23 (subtract 23 from both sides.)
38-23 (solve.)
38-23=15
3/2c=15
2*3/2c=15*2 (multiply 2 from both sides.)
15*2 (solve.)
15*2=30
3c=30
3c/3=30/3 (divide by 3 from both sides.)
30/3 (solve.)
30/3=10
c=10
Answer:
4. dy/dx = -2
8. dy/dx = 1/2 x^(-3/2)
10/ dy/dr = 4 pi r^2
Step-by-step explanation:
4. y = -2x+7
dy/dx = -2(1)
dy/dx = -2
8. y = 4 - x^-1/2
dy/dx = - (-1/2x^ (-1/2-1)
dy/dx = 1/2 x^(-3/2)
10. y = 4/3 pi r^3
dy/dr = 4/3 pi (3r^2)
dy/dr = 4 pi r^2
