Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x = = 8.25 moles
<u>Answer:</u> The percent by mass of ethylene in the equilibrium gas mixture is 3.76 %
<u>Explanation:</u>
We are given:
Initial partial pressure or ethane = 24.0 atm
The chemical equation for the dehydration of ethane follows:
<u>Initial:</u> 24.0
<u>At eqllm:</u> 24-x x x
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the value of x = -1 because partial pressure cannot be negative.
So, partial pressure of hydrogen gas at equilibrium = x = 0.96 atm
Partial pressure of ethylene gas at equilibrium = x = 0.96 atm
Partial pressure of ethane gas at equilibrium = (24-x) = (24 - 0.96) atm = 23.04 atm
To calculate the number of moles, we use the equation given by ideal gas, which follows:
.........(1)
To calculate the mass of a substance, we use the equation:
..........(2)
We are given:
Putting values in equation 1, we get:
We know that:
Molar mass of ethane gas = 30 g/mol
Putting values in equation 2, we get:
We are given:
Putting values in equation 1, we get:
We know that:
Molar mass of ethylene gas = 28 g/mol
Putting values in equation 2, we get:
We are given:
Putting values in equation 1, we get:
We know that:
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 2, we get:
To calculate the mass percentage of ethylene in equilibrium gas mixture, we use the equation:
Mass of equilibrium gas mixture = [235.5 + 9.24 + 0.66] = 245.4 g
Mass of ethylene gas = 9.24 g
Putting values in above equation, we get:
Hence, the percent by mass of ethylene in the equilibrium gas mixture is 3.76 %
1) Left up: a chemical change. We can see new substance (red-blue) is formed from one blue and one red atom.
In chemical change new substances are formed, the atoms are rearranged and the reaction is followed by an energy change.
2) Left down: a chemical change. We can see new substance (red-blue) is formed from two blue and one red atoms.
3) MIddle: a physical change. There is no new substance. Bonds are not broken.
4) Right up: a chemical change. Bonds are broken.
5) Right down: a physical change. Change of state of matter.
