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3 years ago

How do astronomers explain the formation of the milky way galaxy

1 answer:

3 0

Galaxy Formation. One says that galaxies were born when vast clouds of gas and dust collapsed under their own gravitational pull, allowing stars to form. The other, which has gained strength in recent years, says the young universe contained many small "lumps" of matter, which clumped together to form galaxies.

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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

Write the following number using Scientific notation : 13,215,296.50 *

ludmilkaskok [199]

Answer:

13.22x10^7

Explanation:

7 0

3 years ago

Which of the following is NOT a property of bases? Which of the following is NOT a property of bases? Bases dissolve many metals

Hitman42 [59]

Bases dissolve many metals.

8 0

2 years ago

How many atoms are there in 5.00 mol of sulphur (S)?

Mumz [18]

Answer:

3.01 × 10²⁴ atoms S

General Formulas and Concepts:

Chemistry - Atomic Structure

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

5.00 mol S

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$5.00 \ mol \ S(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S} )$ = 3.011 × 10²⁴ atoms S

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

3.011 × 10²⁴ atoms S ≈ 3.01 × 10²⁴ atoms S

6 0

3 years ago

Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of wat

Luba_88 [7]

The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp = vapor pressure lowering

x2 = mole fraction of the of the solute

Number of moles of glycerol = 32.5 g/92 g/mol = 0.35 moles

Number of moles of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp = 0.012 * 23.76 torr

Δp = 0.285 torr

p1 = p° - Δp

p1 = 23.76 torr - 0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:brainly.com/question/14718830

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5 0

2 years ago