Answer:
All elements are neutral
Explanation:
The plum pudding model of the atom indicated that all elements are neutral. The model was proposed by J.J Thomson after he conducted his experiment on the gas discharge tube.
From the experiment he discovered electrons which he called cathode rays.
Therefore, he suggested the plum pudding model of the atom.
The model describes negatively charge sphere surrounded by positive charges to balance them.
Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
M₁V₁ = M₂V₂
0.0952 M * 38.73 mL = M₂* 49.48 mL
M₂ = 0.0745 M
Answer:
Explanation:
mole is the quantity of anything that has the same number of particles found in 12.000 grams of carbon-12. That number of particles is Avogadro's Number, which is roughly 6.02x1023. 1 A mole of carbon atoms is 6.02x1023 carbon atoms. A mole of chemistry teachers is 6.02x1023 chemistry teachers
The reduced forms of the electron carries NAD+ / NADH and FADH / FADH2 have high potential energy.
- NAD& FAD used to donate electrons as a reducing agent, they receive electrons from other molecules and then became reduced.
-FAD is called flow in adenine dinucleotide, it is a redox cofactor and it is in many important enzymatic reactions in metabolism.
Explanation:
Expression for rate of the given reaction is as follows.
Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]
Therefore, the reaction equations by putting the given values will be as follows.
............. (1)
........... (2)
............ (3)
Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.
Therefore, expression for rate of the reaction is as follows.
Rate = ![k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y](https://tex.z-dn.net/?f=k%5BHgCl_%7B2%7D%5Dx%20%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5Dy)
Rate = ![k [HgCl2]1 [C_{2}O^{-2}_{4}]2](https://tex.z-dn.net/?f=k%20%5BHgCl2%5D1%20%5BC_%7B2%7DO%5E%7B-2%7D_%7B4%7D%5D2)
Hence, total order = 1 + 2 = 3
According to equation (1),
k =
Thus, we can conclude that rate constant for the given reaction is
.