A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Answer:
The slope would would be -2
Step-by-step explanation:
16 dollars each because you do 8x5 which equals 40 and do 168-40 which equals 128 / 8 equals 16
How many time that 6688 could into 16 which is 418
By looking at the graph you can rule out choices C and D because the graph given to you is an increasing linear function and C and D represent functions with a decreasing or negative slope.
By looking at the picture the slop of the graph seems to be 4/1 (rise/run) so your slope is 4. And your y-intercept looks like its -4 so your answer is B<span />
