Answer:
I = 11.26 mA
Explanation:
given,
V = 0.7 V length = 80 m
diameter = 0.2 mm = 0.02 cm
radius = 0.01 × 10⁻² m
ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C
A = cross sectional area = π r² = π (0.01 × 10⁻² )²
= 31.4× 10⁻⁹ m²
R = 62.165 Ω
I = 11.26 mA
The average acceleration of the cheetah is 7.75 m/s²
The given parameters;
velocity of the cheetah, v = 31 m/s
time of motion, t = 4 seconds
The average acceleration of the cheetah is calculated as follows;
where;
v is the final velocity
u is the initial velocity
t is the time of motion
Assuming the cheetah started from rest, the initial velocity, u = 0
The average acceleration is calculated as follows;
Thus, the average acceleration of the cheetah is 7.75 m/s²
Learn more here: brainly.com/question/17280180
Answer:
ok
Break the limit
Explanation:
A perfect combination
