The approximate length of the arc intersected by the central angle is 20.94 inches.
The given parameters:
- <em>Radius of the circle, r = 10 inches</em>
- <em>Central angle, </em>
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The approximate length of the arc intersected by the central angle is calculated as follows;
S = rθ
where;
- <em>S is the length of the arc</em>
Substitute the given parameters and solve for the length of the arc
Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.
<em>Your question is not complete, find the complete question below:</em>
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of 
.
Learn more about length of arc here: brainly.com/question/2005046
Answer:
A push or pull exerted on an object
Explanation:
This is simple.
Convert the speed of 45km/h to metres per second (m/s):
45 * 1000m = 45000m per hour.
1 hour = 60 seconds * 60 minutes = 3600 seconds.
45000m/h / 3600 = 12.5m/s
(A quicker way is just to divide by 3.6)
So in 20 seconds it would cover:
12.5m/s * 20s = 250m.
A car travelling at 45km/h would travel 250 metres in 20s.
T is the time for a whole round.
centripetal acceleration = V^2/R,
20 = 40^2 / R, find R = 40^2/20 = 40*40/20 = 80 m, right?
Now, one round is L = 2*pi*R = 2*pi*80 = 160*pi
And T = L/v (distance/speed) = 160*pi/40 = 4*pi seconds, or ~ 12.57 s
Answer:
0.015
Explanation:
Total volume of water coming out = 1.33
Also volume = Cross sectional area*Length covered
Length covered = Velocity *time
=24.5*3.55
=86.97 meter
Let the cross sectional area be A.
1.33 = 86.97*A
A =0.015
