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Semenov [28]
3 years ago
10

Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after

the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision? The final velocity is double train car B’s initial velocity. The final velocity is the same as train car B’s initial velocity. The final velocity is half of train car B’s initial velocity. The final velocity is zero, since train car B will stop.
Physics
2 answers:
Natali [406]3 years ago
7 0

Answer:C The final velocity is half of trained car B's initial velocity.

Explanation:

MatroZZZ [7]3 years ago
6 0

Answer: C i just got it right on e d g e n u i t y :)

Explanation:

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Why does sound travel slower at a cold temperature?
tatyana61 [14]
<h2>Answer:</h2><h2>It is due to a refractment of light.</h2>

Sound moves faster in warmer air than colder air the way bends away from the warm air and back towards of air.

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3 years ago
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A water hose is used to fill a large cylindrical storage tank of
ludmilkaskok [199]

Answer:

maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

Explanation:

Let the nozzle of the hose be at the origin. Then the nearest part of the rim of the tank is at (, ) =  (6, 2) and the furthest part of the rim is at (, ) = (7, 2).

The trajectory of the water can be found as follows:

x = (v_o cos45) t

y =  (v_o sin45) t - \frac{1}{2}gt^2

Now from above two equations we have

y = x - \frac{gx^2}{v_o^2}

now we know that height of the cylinder is 2D so we have

x - \frac{gx^2}{v_o^2} = 2D

by solving above equation we have

x = \frac{v_o^2 \pm v_o^2\sqrt{1 - \frac{8gD}{v_o^2}}}{2g}

now we know that maximum value of x is 7D

so the maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

6 0
3 years ago
A MEMS-based accelerometer has a mass of m = 2 grams, an equivalent spring constant of k = 5 N/m, and an equivalent damping coef
pychu [463]

Answer:

The natural frequency = 50 rad/s = 7.96 Hz

Damping ratio = 0.5

Explanation:

The natural frequency is calculated in this manner

w = √(k/m)

k = spring constant = 5 N/m

m = mass = 2 g = 0.002 kg

w = √(5/0.002) = 50 rad/s

w = 2πf

50 = 2πf

f = 50/(2π) = 7.96 Hz

Damping ratio = c/[2√(mk)] = 0.1/(2 × √(5 × 0.002)) = 0.5

5 0
3 years ago
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3 and the pressure increases from 1.00×105 Pa
Alborosie
<h2>The work done = - 2 x 10⁴ J</h2>

Explanation:

In the first case , the volume is kept constant and pressure varies .

In isothermal process  , the work done

W₁ = V x ΔP

here V is the volume of gas and ΔP is the change in pressure

Thus W₁ = 0

Because there is no change in volume , therefore displacement is zero .

In second case pressure is constant , but volume changes

Thus W₂ = P x ΔV

here P is the pressure  and ΔV is the change in volume

Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J

The total work done W = - 2 x 10⁴ J

Because the work done in compression is negative .

7 0
3 years ago
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