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goblinko [34]
3 years ago
5

Use the function below to find F(-2) F(X)= 3^x

Mathematics
2 answers:
Sonja [21]3 years ago
7 0

Answer:

\displaystyle f(-2) = \frac{1}{9}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Terms/Coefficients

Functions

  • Function Notation

Exponential Property [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 3^x

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           \displaystyle f(-2) = 3^{-2}
  2. Rewrite [Exponential Property - Rewrite]:                                                      \displaystyle f(-2) = \frac{1}{3^2}
  3. Exponents:                                                                                                       \displaystyle f(-2) = \frac{1}{9}
german3 years ago
4 0

Answer:

0.11111 repeating

Step-by-step explanation:

3^-2

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Will mark brainliest !
fiasKO [112]

Answer:

x = 9

y = 6

Step-by-step explanation:

  1. Divide 15 by 2: 15 ÷ 2 = 7.5
  2. Subtract 0.5 from 7.5 (this will later be added back): 7.5 - 0.5 = 7
  3. Subtract 1 from 7 (she wants to buy at least 2 more children books): 7 - 1 = 6
  4. Subtract 6 from 15 (6 being the number of puzzle books, 15 being the total number of items): 15 - 6 = 9 (number of children books)
4 0
3 years ago
Read 2 more answers
Find the probability of randomly rolling 2 standard dice and having a sum that is EVEN or GREATER THAN 9.
Ede4ka [16]

Answer:

Hence, the probability of randomly rolling 2 standard dice and having a sum that is EVEN or GREATER THAN 9 is 2/3

Step-by-step explanation:

Let A be the event that the sum of two dice is even

Then P(A) will be the probability of having even sum

As the sample space is already given in the image

n(S) = 36

A = {(1,1) , (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)}

n(A) = 18

So,

P(A) = n(A)/n(S)

= 18/36

= 1/2

Let B be the event that the sum is greater than 9

B = {(4,6), (5,5), (5,6), (6,4), (6,5), (6,6)}

n(B) = 6

P(B) = n(B)/n(S)

= 6/36

= 1/6

Now we have to find P(A∪B) i.e. P(A or B)

P(A∪B) = P(A) + P(B)

= 1/2 + 1/6

= (3+1)/6

=4/6

=2/3

Hence, the probability of randomly rolling 2 standard dice and having a sum that is EVEN or GREATER THAN 9 is 2/3 ..

7 0
4 years ago
Read 2 more answers
Solve the following equation 3 by X + 1 is equal to 5 by 2 X linear equation​
dangina [55]

Answer:

  x  = 5

Step-by-step explanation:

A by B is simply \frac{A}{B}

    3 by x + 1 is \frac{3}{x + 1}  

    5 by 2x is \frac{5}{2x}  

So, the equality is ;

                \frac{3}{x + 1} = \frac{5}{2x}  

Cross multiply and solve the inequality;

         3(2x) = 5(x + 1)

         6x  = 5x + 5

          6x -5x = 5

              x  = 5

3 0
3 years ago
Help me please! <br><br> a = 3, b = 5, and c = 7. What is m&amp;Bº to the nearest tenth?
Anastaziya [24]

Answer: m∡B°=38,2°.

Step-by-step explanation:

a=3,  b=5,  c=7  ∡B°=?

b^2=a^2+c^2-2*a*ccosB^0\\2*a*c*cosB^0=a^2+c^2-b^2\\cosB^0=\frac{a^2+c^2-b^2}{2*a*c} \\cosB^0=\frac{3^2+7^2-5^2}{2*3*7} \\cosB^0=\frac{9+49-25}{2*3*7} \\cosB^0=\frac{33}{42} \\cosB^0=\frac{11}{14}\\

m∡B°=arccos(\frac{11}{14})

m∡B°≈38,2°.

Good luck!

4 0
2 years ago
Please help asap will give brainliest!!
Anit [1.1K]

Answer:

802

Step-by-step explanation:

802

6 0
3 years ago
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