Question

If it takes 6 sec for a ball to strike the ground when it it is released from rest, determine the height in meters of the building from which it was released. Take (g - acceleration due to gravity to be 10 m/sec) 60 m 120 m 140 m 180 m

Answer 1

Answer:

The height of the building is 180 meters.

Explanation:

It is given that,

Time taken for a ball to strike the ground, t = 6 sec

It is released from the rest. We need to find the height of the building from which it is released. It can be calculated using the equation as follows :

$s=ut+\dfrac{1}{2}at^2$

Here, a = g and u = 0

So, $s=0+\dfrac{1}{2}gt^2$

$s=\dfrac{1}{2}\times 10\ m/s^2\times (6\ s)^2$

s = 180 meters

So, the height of the building is 180 meters. Hence, this is the required solution.