<span> It is 0 m/s. At the very top of its flight is right between when it is going up and going down; this is the ephemeral moment when it is perfectly still. </span>
Answer:2 amperes
Explanation:
Voltage=120v
Total resistance=15+15+30
Total resistance=60 ohms
Current=voltage ➗ resistance
Current=120 ➗ 60
Current=2 amperes
We will first convert all units to meters and then solve the problem.
We are given that:
1000 mm = 1 m
120 mm = ?? meters
using cross multiplication:
120 mm = (120*1) / 1000 = 0.12 m
Now, when the two objects are placed over each other, their total height is the result of summation of both heights, therefore:
total height = 0.12 + 1.5 = 1.62 m
Based on the above calculations, the correct choice is:
<span>b) 1.62 m </span>
Answer: 0.258
Explanation:
The resistance 
of a wire is calculated by the following formula:
(1)
Where:
is the resistivity of the material the wire is made of. For aluminium is 
and for copper is 
is the length of the wire, which in the case of aluminium is 
, and in the case of copper is 
is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:
(2) Where 
is the diameter of the circumference.
For aluminium wire the diameter is 
and for copper is 
So, in this problem we have two transversal areas:
<u>For aluminium:</u>
(3)
<u>For copper:</u>
(4)
Now we have to calculate the resistance for each wire:
<u>Aluminium wire:</u>
(5)
(6) Resistance of aluminium wire
<u>Copper wire:</u>
(6)
(7) Resistance of copper wire
At this point we are able to calculate the ratio of the resistance of both wires:
(8)
(9)
Finally:
This is the ratio
Answer:
64.5
Explanation:
(m1 + m2) v initial = (m1 * v1 final) + (m2 * v2 final)
(92 + 8)(-7) = (92 x 2) + (8 x v2 final)
(100)(-7) = (184) + (8 x v2 final)
-700 = (184) + (8 x v2 final)
-516 = (8 x v2 final)
-516/8 = v2 final
-64.5 = v2 final
