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2 years ago

What is the net force acting on a 0.15 hockey puck accelerating at 12 m/s/s?

Physics

1 answer:

svetoff [14.1K]2 years ago

3 0

1.8N

Explanation:

Given parameters:

Mass of the hockey puck = 0.15kg

Acceleration = 12m/s²

Unknown:

Net force = ?

Solution:

According newton's second law of motion "the net force on a body is the product of its mass and acceleration".

Force = mass x acceleration

Input the variables;

Net force = 0.15 x 12 = 1.8N

learn more:

Newton's law of motion brainly.com/question/11411375

#learnwithBrainly

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What do the mitochondria do??

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Mitochondria breaks down sugar to release energy to the cell.

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3 years ago

The current through an inductor of inductance L is given by I(t) = Imax sin(ωt).

sammy [17]

Answer:

(a) $emf_L=-LI_{max}\omega cos(\omega t)$

(b) neither increasing or decreasing

Explanation:

The current through an inductor of inductance L is given by:

$I(t)=I_{max}sin(\omega t)$ (1)

(a) The induced emf is given by the following formula

$emf_L=-L\frac{dI}{dt}$ (2)

You derivative the expression (1) in the expression (2):

$emf_L=-L\frac{d}{dt}(I_{max}sin(\omega t))\\\\emf_L=-LI_{max}\omega cos(\omega t)$

(b) At t=0 the current is zero

(c) At t = 0 the emf is:

$emf_L=-\omega LI_{max}$

w, L and Imax have positive values, then the emf is negative. Hence, the induced emf is opposite to the flow of the charge carriers.

(d) read the text carefully

6 0

2 years ago

A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad

jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

$T=\frac{mv^2}{r}$

$205=\frac{0.477\times v^2}{0.725}$

$0.477v^2=148.625$

$v^2=311.5828$

v = 17.651 m /sec

8 0

3 years ago

a 55.0 kg person having a denity of 1010 kg/m^3 is underwater. What is the net force acting on the person?

bija089 [108]

Answer:

The net force acting on the person is 5.34 N acting upwards

Explanation:

The information given are;

Mass of the person = 55.0 kg

Density of the person = 1010 kg/m³

Body volume of the person = Mass/Density = 55/1010 = 0.0545 m³

Weight of the person = Mass × Gravity = 55 × 9.81 = 539.55 N↓

Where the density of water = 1000 kg/m³, we have;

Upthrust = weight of the water displaced = Mass of the water displaced × Gravity

Mass of the water displaced = Density of water × Volume of the water

Mass of the water displaced = Density of water × Body volume of the person

= 1000 × 0.0545 = 54.5 kg

The Upthrust = 54.5 × 9.81 = 534.21 N↑

Given that the net force, $F_{Net}$ acting is the sum of the mass of forces acting on the person which are the weight acting downward and the upthrust acting upwards

We have;

F(Net) = 534.21↑ - 539.55↓ = 5.34 N↑

The net force acting on the person = 5.34 N upwards.

6 0

2 years ago

Odysseus has returned from his epic voyage across the seas and gets off his boat at the end of a 50 meter pier. His beloved Pene

OlgaM077 [116]

Answer:

We know that:

Distance between Odysseus and Penelope = 50m

Speed of Odysseus = So = 4m/s

Speed of Penelope = Sp = 6m/s.

Now we want to find the equation of motion for Odysseus.

First, let's find the amount of time that he is moving, we know that when he meets with Penelope, he will stop moving.

Now they weel meet each other when the total distance traveled by both of them is equal to 50m.

Then, recalling that:

Distance = Time*speed.

50m = 4m/s*t + 6m/s*t = 10m/s*t

t = 50m/10m/s = 5s

They will move for 5 seconds.

Now we can write the movement equation for Odysseus as:

p(t) = 4m/s*t + p0 for (0s ≤ t ≤ 5s)

Where p0 is the initial position of Odysseus, and because we can put our coordinate axis where we want, we can define p0 = 0m.

Then the position of Odysseus is:

P(t) = 4m/s*t if 0s ≤ t ≤ 5s

P(t) = 4m/s*5s = 20m if t > 5s.

The second piece says that for t larger than 5 seconds, he will not move (at least for a given amount of time)

8 0

2 years ago