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2 years ago

Help with 5 math questions pls!

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

6 0

Answer:

1. 9

2. 6√(2)/8.49

3. √(12)/3.46

4. √(50)/7.07

5. 1584

Step-by-step explanation:

Use pythagorean theorem for all of these triangles which is a^2+b^2 = c^2, for the problems with writing, just break it down and draw out a triangle and solve it from there and plug in the right numbers and solve

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Need help with this :(

emmainna [20.7K]

Answer:

B. m = $\frac{3}{2}$ , y-int = 3

Step-by-step explanation:

To find the slope of the line, we need to plot two points

(2, 6) (-2, 0)

m = slope

Then use the Slope-Formula to Solve for the slope

m = $\frac{y2-y1}{x2-x1}$

m = $\frac{0-6}{-2-2}$

m = $\frac{-6}{-4}$

m = $\frac{6}{4}$

m = $\frac{3}{2}$

The Slope is $\frac{3}{2}$

The y-intercept is 3 because the line is going 3 units upwards on y axis!

Equation: y = 3/2x + 3

Slope: 3/2

y-intercept: 3

5 0

2 years ago

Read 2 more answers

8 - 1/3 x = 16 please help

Len [333]

Hope you can understand the handwriting :)

7 0

2 years ago

Geometry Help PLZ!!!

Eva8 [605]

Answer:

Step-by-step explanation:

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3 years ago

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

8 0

3 years ago

Is (2, 1) a solution to this system of inequalities?<br><br> 3x + 7y ≥ 13<br> 2x + y < 5

Gnoma [55]

Answer:

Pay attention in class

Step-by-step explanation:

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2 years ago