Total amount saved in 1st case :
![S_1=400+20t_1](https://tex.z-dn.net/?f=S_1%3D400%2B20t_1)
Total amount saved in 2nd case :
![S_2=100+40t_2](https://tex.z-dn.net/?f=S_2%3D100%2B40t_2)
( Here
are number of months )
Let, after x months the amount saved in both cases is same.
So,
![S_2=S_1\\\\100+40x=400+20x\\\\20x = 300\\\\x = 15\ months](https://tex.z-dn.net/?f=S_2%3DS_1%5C%5C%5C%5C100%2B40x%3D400%2B20x%5C%5C%5C%5C20x%20%3D%20300%5C%5C%5C%5Cx%20%3D%2015%5C%20months)
Amount saved :
![S_1=400+20(15) =\$ 700](https://tex.z-dn.net/?f=S_1%3D400%2B20%2815%29%20%3D%5C%24%20700)
![S_2=100+40( 15)= \$700](https://tex.z-dn.net/?f=S_2%3D100%2B40%28%2015%29%3D%20%5C%24700)
Hence, this is the required solution.
Answer:
Yes
Step-by-step explanation:
They add up to 90 degrees.
He spends 30 hours at work from 10 hours of recreational time
Answer:39
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the ...
y variable=139x/ 5 2/5-
x variable =5y/139+2/139