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3 years ago

a house cost 120,000 whenit was purchased. the value of the house by each year find the growth of each month

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

144,000,000 because you need to times 120,000 time 12 and that’s what you get

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What is the answer for the equation 4|x+1/3|=20 ?

Llana [10]

I hope this helps you...

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3 years ago

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What are the coordinates of the hole in the graph of the function f(x) ?

Vinvika [58]

ANSWER

$(3, \infty )$

EXPLANATION

The given function is

$f(x) = \frac{ {x}^{2} - 9}{x - 3}$

When we plug in x=3 into this function, we obtain,

$f(3) = \frac{0}{0}$

This means that the function is discontinuous at x=3.

We need to simplify the function to obtain,

$f(x) = \frac{(x - 3)(x + 3)}{(x - 3)}$

This implies that,

$f(x) = x + 3$

The graph this function is a straight line that is continuous everywhere.

To graph

$f(x) = \frac{ {x}^{2} - 9}{x - 3}$
we draw the graph of

$f(x) = x + 3$
and leave a hole at x=3.

See diagram in attachment.

Hence the coordinates of hole is

$(3, \infty )$

6 0

3 years ago

Please HELP!!!!!!! I don't get it

Akimi4 [234]

C Because the other answers 2 or1 pound that's more than the amount in the question asks for

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3 years ago

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The ratio of the number of student in mr. Moore’s class compared to the number of student in miss Henry’s class is 5:4. The rati

Ahat [919]

Answer:

10:9

Step-by-step explanation:

First ratio is 5:4. 4 is equal to Henry class

If you múltiply the ratio by 2 you get

10:8, This ratio can be compared because now Henry class has 8

2(5:4)

10:8

8:9

Meaning that the answer is 10:9

7 0

3 years ago

there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and

Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

$n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}$

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0

3 years ago