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3 years ago

If the area of a circle is 58 square feet, find the circumference

Mathematics

2 answers:

miv72 [106K]3 years ago

5 0

It is 58 feet , You use the formula 3.14 x D .....

Hope it help ya .

enyata [817]3 years ago

3 0

Hi there! C=2πa=2*π*58=26.99621 ft. Therefore, the answer is 27 ft.

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Jordan is mixing water and flour to make tortillas. The number cups of water, w needed for f cups of flour is described by the e

Tresset [83]

Answer:

$1\frac{1}{3}$ cups of flour.

Step-by-step explanation:

Given that:

$w$ is the number of cups of water to be mixed with flour for making tortillas.

$f$ is the number of cups of flour to be mixed with water for making tortillas.

Relation between $w$ and $f$ is given by the equation:

$w=0.75f$

To find:

Number of cups of flour to be added if number of cups of water to be used is 1.

Solution:

We are given an equation with two variables.

Value of one variable is given and we have to find the value of other variable.

$1=0.75f\\\Rightarrow f = \dfrac{1}{0.75}\\\Rightarrow f = 1.33$

Number of cups of flour to be added = $1\frac{1}{3}$

6 0

2 years ago

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

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3 years ago

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professor190 [17]

Answer:

x^2+15

Step-by-step explanation:

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Licemer1 [7]

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KATRIN_1 [288]

Answer:

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