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2 years ago

8

one lap around a track is equal to one fourth of a mile. A horse ran a distance of 9 laps in 2 minutes and 30 seconds. What was

the horse's average speed in miles per hour

1 answer:

Goryan [66]2 years ago

5 0

13.3 repeating all you have to do is convert them into seconds and divide them by nine

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Gordon types 43 3/4 pages in 3 1/2 hours. What is his rate in pages per hour

Olegator [25]

Answer:

His rate is 12 1/2 pages per hour.

Step-by-step explanation:

Given that,

Gordon types 43 3/4 pages in 3 1/2 hours or Gordon types 175/4 pages in 7/2 hours./ We need to find its rate in pages per hour. So,

$R=\dfrac{\dfrac{175}{4}\ \text{pages}}{\dfrac{7}{2}\ \text{hour}}\\\\R=\dfrac{175}{4}\times \dfrac{2}{7}\\\\R=12.5\ \text{pages per hour}\\\\R=12\dfrac{1}{2}\ \text{pages per hour}$

Hence, his rate is 12 1/2 pages per hour.

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2 years ago

BRIANILEST!!!Hassan lined up the interior angles of the triangle along the line below.

stiks02 [169]

A straight line = 180 degrees.

Subtract the 2 known angles from 180:

180 - 112 - 38 = 30 degrees

3 0

3 years ago

Read 2 more answers

60.2 rounded to the nearest hundredth

Anna11 [10]

It’s gunna be 60.2 I believe

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2 years ago

It is 76°f at the 6000-foot level of a mountain, and 49°f at the 12,000-foot level of the mountain. write a linear equation to f

valina [46]

Answer:

$t(x) = 103 -0.0045x$

Step-by-step explanation:

We are given the following in the question:

Let the equation:

$t(x) = a + bx$

be the linear equation that represent temperature at an elevation x.

Temperature at 6000-foot level = 76 f

$76 = a + 6000b$

Temperature at 12000-foot level = 49 f

$49 = a + 12000b$

Solving the two equation, we get,

$76-49 = -6000b\\27=-6000b\\\\b = \dfrac{-27}{6000}\\\\b = -0.0045\\76 = a + (-0.0045)6000\\76 = a -27\\a = 76 + 27\\a =103$

Thus, we can write the linear equation as:

$t(x) = 103 -0.0045x$

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2 years ago

Which angle below is another name for ZABC?

Liula [17]

Answer is none of these

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2 years ago