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Norma-Jean [14]
3 years ago
11

Find 0.5 of 60 and 130% of 80

Mathematics
1 answer:
wariber [46]3 years ago
7 0
.5 (50%) of 60 is 30. 130% of 80 is 104.
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Graphs B and D.

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The graph of a function has at most one y value for each x value.

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The library has 157 chairs and 14 tables. If the same number of chairs is placed at each table, how
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2 years ago
Given: △ABC, AB=5 square root 2 <br><br>m∠A=45°, m∠C=30°<br><br>Find: BC and AC
hichkok12 [17]

Answer:

Part a) BC=10\ units

Part b) AC=13.66\ units

Step-by-step explanation:

step 1

Find the length side BC

Applying the law of sines

we know that

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

we have

AB=5\sqrt{2}\ units

A=45^o

C=30^o

substitute

\frac{5\sqrt{2}}{sin(30^o)}=\frac{BC}{sin(45^o)}

solve for BC

BC=\frac{5\sqrt{2}}{sin(30^o)}(sin(45^o))

BC=10\ units

step 2

Find the measure of angle B

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

so

m\angle A+m\angle B+m\angle C=180^o

substitute the given values

45^o+m\angle B+30^o=180^o

75^o+m\angle B=180^o

m\angle B=180^o-75^o

m\angle B=105^o

step 3

Find the length side AC

Applying the law of sines

we know that

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

we have

AB=5\sqrt{2}\ units

A=45^o

B=105^o

substitute

\frac{5\sqrt{2}}{sin(30^o)}=\frac{AC}{sin(105^o)}

solve for AC

AC=\frac{5\sqrt{2}}{sin(30^o)}(sin(105^o))

AC=13.66\ units

4 0
3 years ago
PLEASE ANSWER THIS CORRECTLY I WILL GIVE YOU BRAINLIEST IF ITS CORRECT. I NEED THIS, I CANT DO ANYTHING FOR CHRISTMAS IF I FAIL
Sophie [7]

Answer:

1 is 50 min

Step-by-step explanation:

big brain

7 0
3 years ago
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