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MaRussiya [10]
1 year ago
9

out of 150 students appeared in an examination 60% of the students passed in math 50% in Science and 20% in both subjects how ma

ny students where failed in both subjects ?by using Venn diagram find the number of student Wawa passed in maths only .​
Mathematics
1 answer:
jeka57 [31]1 year ago
5 0

Answer:

5000 students

Step-by-step explanation:

Let total number of students appeared in the exams is x.

20% of x have failed in both maths and science.

Here,in maths 60% of students passed.

%ag of students failed in maths= 40%

%ag of students failed in math — % of students failed in both maths and science = students passed in science but failed in maths i.e. 40–20 = 20%.

Likewise as 70% of students passed science

So 30% failed in science.

And Students failed in science only but passed in maths= %ag of students failed in science- % of students failed in both maths and science.

i.e. 30–20= 10%.

Given 2500 number of students passed in both maths and science = 100–(students failed in both maths and science+ students failed only in maths and passed in science+ students failed only in science but passed in maths)%

= 100–(20+20+10)= 50% of students passed both.

50% of x = 2500

50x/100= 2500

=> x= 5000.

So total number of students appeared in exam is 5000 in number

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Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

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Step-by-step explanation:

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The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

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In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

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And we want to find this probability:

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e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

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