Answer:
Step-by-step explanation:
Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.
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<u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>
• The sum of n terms of an AP is
![\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Corange%7B%5Csf%20S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D%20%7D%7D)
• nth term of an AP is given by ,
All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
Answer:
18225
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
A constant correlation is essentially when the points on a scatter plot do not show any type of pattern or correlation; the points are literally scattered rather randomly, which would cause the graph to neither increase nor decrease.
Meanwhile, a positive correlation means that the points on the plot follow a line with a positive slope. In other words, it increases to the right.
Thus, the answer is C.
Hope this helps!
<h3>
Answer: (n-1)^2</h3>
This is because we have a list of perfect squares 0,1,4,9,...
We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.
In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.
You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".
All of this only applies to sequence A.
side note: n is some positive whole number.
