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Strike441 [17]
3 years ago
5

A line with a slope of 1 passes through the point (0, 2)What is its equation in slope-intercept form?

Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:

y=x+2

Step-by-step explanation:

y-y1=m(x-x1)

y-2=1(x-0)

y-2=1(x)

y-2=x

y=x+2

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A diver descends from an elevation of 6 feet below sea level to an elevation of 98 feet below sea level in 4 equal intervals.wha
Inessa [10]
Hmmm thats a tricky question
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Jack was 99 years older than priscilla. together their ages totaled 167167 years. what were their​ ages?
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Priscilla's age was 83,534 while Jack's age was 83,633.
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3 years ago
What is the domain of the function y= square root of X plus 4​
kumpel [21]

Answer: all real numbers

Step-by-step explanation:

the domain for any function is always, all real numbers or in other words, negative infinity to positive infinity.

5 0
3 years ago
6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that thei
BaLLatris [955]

Answer:

96

Step-by-step explanation:

Using side b as the base, 4 points makes 3 bases (the space in between).  With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments.  This equals 6 bases. Each of these can connect to a point on line a. 6x6=36

Using side a as the base, 6 points makes 5 bases.  With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments.  This equals 15 bases.  Each of these can connect to a point on line b.  15x4=60

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5 0
3 years ago
Read 2 more answers
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
gavmur [86]

Answer:

The profit function is:

P(x)=-x^2+1280x-3300

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

R(x)=1300x-x^2

And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

P(640)=-(640)^2+1280(640)-3300=406300

5 0
3 years ago
Read 2 more answers
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