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3 years ago

Help me understand please ;-;

2 answers:

7 0

Standard form for first one is
ax+by=c

6y-12=-3x
add 3x both sides
3x+6y-12=0
add 12
3x+6y=12

second one
distribute (don't forget double negative y)
10-2x+2y=3x+1
minus 3x both sides
10-5x+2y=1
minus 10 both sides
-5x+2y=-9

the equations are
3x+6y=12
-5x+2y=-9

mart [117]3 years ago

3 0

The standad form of linear equation is of the form Ax + By = C, where A, B and C are integers.
Here, the standard form of the eduation 6y - 12 = -3x is 3x + 6y = 12

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<span>Check the chart for a better understanding:
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Consider expression $\sqrt{a+ \sqrt{b} }$ . If this expression becomes an integer, then b=4,9,16,25, because then $\sqrt{b} =$ 2,3,4,5, respectively. In other cases $\sqrt{b}$ is not integer and thus the expression $\sqrt{a+ \sqrt{b} }$ also is not integer.

1. b=4, then $\sqrt{a+ \sqrt{b} }=\sqrt{a+2}$ . Here a=2,7 (in other cases $\sqrt{a+2}$ is not integer). When a=2, $\sqrt{a+2}=\sqrt{2+2}=2$ and when a=7, $\sqrt{a+2}=\sqrt{7+2}=3$ .

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3. b=16, then a=5 and $\sqrt{a+ \sqrt{b} }= \sqrt{a+4}=\sqrt{5+4}=3$ .

4. b=25, then a=4 and $\sqrt{a+ \sqrt{b} }=\sqrt{a+5}=\sqrt{4+5}=3$ .

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