I don’t think their is a solution to this equation
because if you expand the second half it is= 24y-24 which would make the equation
- 24y-22=24y-24
and because the number next to the y is the same on both sides, no matter what y is if we subtract different numbers from each side we will never get the same value for each side of the =
Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price

Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.
I believe the answer is 1064.
P.s. your cute matsuki <3