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Daniel [21]
3 years ago
9

You buy a shirt at Kohl’s that costs 27.50 but it’s 20% off. How much is the new price of the shirt

Mathematics
2 answers:
Sav [38]3 years ago
8 0

Answer:

22

Step-by-step explanation:

Basically, multiply .20 by 27.50, and get 5.5. Now, subtract 27.50 by 5.5 to get 22.

Drupady [299]3 years ago
6 0

Answer:

$22

Step-by-step explanation:

$27.50 x $0.80 = $22

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Nori had 2 bags of apples. He used 1. bags of apples to make pies. How
Inessa05 [86]

Answer:

8/12 left

Step-by-step explanation:

8/12 of a bag left

2 1/12 = 25/12

1 5/12 = 17/12

25-17 = 8

The answer is 8/12

5 0
2 years ago
Read 2 more answers
Select all the statements that describe the expression 5 + 2x.
FromTheMoon [43]

It's A that's correct!!!!

8 0
3 years ago
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What number is 35% of 80?
Wittaler [7]
What number is 35% of 80?

35/80 

35 ÷ 80 = <span>0.4375

</span>0.4375 × 100 = <span>43.75
</span><span>43.75%
</span>
43.75% is 35% of 80. 
4 0
3 years ago
Need help with Calculus 1 inverse trig functions
lidiya [134]

Answer:

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}

Where u is a function of x as provided:

y=3tan^{-1}(x+\sqrt{1+x^2})

If we set

u=(x+\sqrt{1+x^2})

Then

\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}

\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}

Taking the derivative of y

y'=3[tan^{-1}(x+\sqrt{1+x^2})]'

Using the change of variables

\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}

\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}

Operating

\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}

\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}

8 0
3 years ago
What is 0.55 in a decimal as a fraction in simplest form ?
anzhelika [568]
0.55 is equal to 55/100, and by dividing the numerator and denominator by 5, we get 11/20. Hope this helps!
8 0
2 years ago
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