Answer:
an=-2n-3
Step-by-step explanation:
The approximate mass of the spherical weight is 51 pounds
To answer the question, we need to know what the mass of the sphere is
<h3>Mass of the sphere</h3>
The mass of the sphere m = ρV where
- ρ = density of steel = 0.284 lb/in³ and
- V = volume of sphere = 4πr³/3 where
- r = radius of sphere = 3.5 in
So, m = ρV
= ρ4πr³/3
Substituting the values of the variables into the equation, we have
m = ρ4πr³/3
= 0.284 lb/in³ × 4π(3.5 in)³/3
= 0.284 lb/in³ × 4π × 42.875 in³/3
= 48.706π lb/3
= 153.014 lb/3
= 51 lb
The approximate mass of the spherical weight is 51 pounds
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So you want to take out the GCF first.
The GCF is 2x
2x(x^2+2x+4)
This is your final answer because there is not other way to factor.
Answer:
Step-by-step explanation:
to solve the volume you must multiply the sides together
you would multiply the length by the width by the height
so you would multiply 7 and 15 and 10
Answer:
Step-by-step explanation:
Given
ET = 120 V
, R = 30 Ω,
XL = 40 Ω.
To find = IR=?
as in circuit inductor and resistor are parallel so ET =EL = ER = 120V
IR = current through resistor = IR = ER/ R
= 120V /30Ω.
= 4 ampere.
