Answer:
(y^2 + 3y) / (y^2 - 6y + 9)
Factored form: [y*(y+3)] / [(y-3)^2]
Step-by-step explanation:
We need to find the following product:
(2y / y-3) / ((4y-12) / (2y+6))
We have a division of fractions. We can transform this in a product, where we have the first fraction multiplied by the inverse of the second fraction. So, we have that:
(2y / y-3) * ((2y+6) / (4y-12))
= 2y*(2y+6) / ((y-3)*(4y-12))
= [2y * 2 * (y+3)] / [4 * (y-3) * (y-3)]
= [y*(y+3)] / [(y-3) * (y-3)]
= (y^2 + 3y) / (y^2 - 6y + 9)
