Answer:
x=2ln(2)/(2ln(2)-ln(3))
Step-by-step explanation:
ln(4^x-1)=ln(3^x)
(x-1)ln(4)=ln(3^x)
(x-1)ln(4)=xln(3)
ln(4)x-ln(4)=xln(3)
ln(4)x=ln(3)x+2ln(2)
2ln(2)x-ln(3)x=2ln(2)
(2ln(2)-ln(3))x=2ln(2)
Therefore, x=2ln(2)/(2ln(2)-ln(3))
The formula for depreciation is:

Where x = Initial value,
y= Amount after depreciation.
r= Rate of depreciation,
t = time (in years)
According to given problem,
x = 1040, y= 944 and t = 12 months =1 year.
So, first step is to plug in these values in the above formula, So,

944 = 1040 (1 -r)
Divide each sides by 1040.
0.907692308 =1 - r
0.907692308 - 1 = -r Subtract 1 from each sides.
-0.092307692 = -r
So, r = 0.09 or 9%.
Now plug in 0.09 in the above equation to get the depreciation equation. So,

So, 
b) To find the value of the bike after 5 months,
plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.
So, 
y = 1040 * 0.961465659
y = 999.9242852
y = 1000 (Rounded to nearest integer).
Hence, the value of the bike after 5 months is $1000.
Answer:
A. One point greater than the last test grade.
Step-by-step explanation:
One point greater than the last test grade can be written as an expression:n + 1
The difference of Gina’s score and one can be written as an expression:
n - 1
The total cost less one dollar can be written as an expression: n - 1
One minute less than Mickey’s previous time can be written as an expression: n - 1
8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.