You just plug in the values.
[3*(-2)]^3 - (-2 - 4*5)^2
(-6)^3 - ( - 2 - 20)^2
-216 - (-22)^2
-216 - (484)
-216 - 484
-700
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
It will be 50,000 =10*5,000
Answer:
yes it's a solution. I think. I don't really know this
