All categories

3 years ago

Plz help me 8+x^2-11

Mathematics

2 answers:

likoan [24]3 years ago

6 0

Answer:

-3 + x^2

Step-by-step explanation:

8+x^2-11

First combine the like terms.

so..

8-11 = -3

= -3 + x^2

but we don't know the value of x so we just leave it as it is.

And they both are not like terms so we cant solve them together so you stop there

Hope that helped!

tensa zangetsu [6.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

Simplify the numbers for you to get

x^2 stays the same

-11 = 8 = -3

You might be interested in

the midpoint of [KL] is (-8, 1). one endpoint is K(-6, 5). find the coordinates of the other endpoint L

ExtremeBDS [4]

the correct question is

The midpoint of kl is m(–8, 1). one endpoint is k(–6, 5). find the coordinates of the other endpoint l.

we know that

the formula of midpoint is

Xm=(x1+x2)/2----> 2*Xm=x1+x2------> x2=2*Xm-x1

Ym=(y1+y2)/2----> 2*Ym=y1+y2------> y2=2*Ym-y1

let

(x1,y1)-------> (–6, 5).

(Xm,Ym)-----> (-8,1)

find (x2,y2)

x2=2*Xm-x1-----> 2*(-8)-(-6)----> -10

y2=2*Ym-y1----> 2*(1)-5-----> -3

the point l is (-10,-3)

3 0

3 years ago

Lazy help me asap.......

damaskus [11]

Answer:

3 3/11 im sure its correct.

4 0

3 years ago

Read 2 more answers

Help<br> I dont know the answer im not very smart

Dahasolnce [82]

The domain of G is 4 and the range of G is 9 (domain=x, range=y :))

8 0

2 years ago

Can anyone rewrite the quadratic function in standard form?

ycow [4]

Answer:

So we first open multiply the parenthesis by 9. 9x+5 is what it is. Now we need to simply it even more with the 2 parenthesis

(9x+5)(x+1) = 9x^2+9x+5x+5 = 9x^2+14x+5

<h2><u>Answer: 9x^2+14x+5</u></h2>

3 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago