Answer asap pls no wrong answers pls
1 answer:
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Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer: First option.
Step-by-step explanation:
The complete exercise is attached.
In order to solve this exercise, it is necessary to remember the following property:
The Multiplication property of Equality states that:
In this case, the equation that Jada had is the folllowing:
Jada needed to solve for the variable "x" in order to find its value.
The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:
As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by <em> </em>and the right side by
.
Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.
