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Elodia [21]
2 years ago
11

Write in standard notation (1/sqrt2-1/sqrt2 i)^6

Mathematics
1 answer:
vesna_86 [32]2 years ago
7 0
Hello,

z=(1/√2-1/√2 i)^6=1/8*(1-i)^6=1/8*(√2∡-45°)^6=1/8*8∡-270°=1∡90°=i
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