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kotegsom [21]
3 years ago
9

Convert 30 to hexadecimal ​

Computers and Technology
1 answer:
Delvig [45]3 years ago
6 0

Answer:

1E

Explanation:

Here is a table to help you. Similar to a multipication table, just follow either the number 3 down to A (aka 10) or 6 x 5 and you will find your answer of

1E = 30

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What is indirect program memory addressing? Explain the working of the following instructions?
Elanso [62]
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  • Instruction is used to direct towards a register that displays the results of the variables.
  • The register, in turn, refers to that variable's address in simplistic words. As just a result, it is indeed considered a passive program, memory address.

The instructions operate as follows:

a)

JMP AX :

  • The JMP instruction is being used to execute an unconditional jump.
  • AX is indeed the label's name.
  • JMP AX codes are being used to transfer control of the flow program to the AX label.

b)

JMP LIST:

  • The JMP command can be used to execute an unconditional jump, JMP LIST[DX] is the label's name.  
  • The JMP LIST[DX] program is being used to transfer control of its flow programs to the specified section.
  • It is the segment to which the flow control is transmitted.

c)

JMP NEAR PTR[DI+3]: 

  • Unconditional jumps could be done with the JMP command as you'll see, the label is JMP NEAR PTR[DI+3].
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  • The close keyword indicates that perhaps the code segment would be in the line of code being nearby.

Learn more:

brainly.com/question/20320915

4 0
3 years ago
How was WiFi discovered?
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Answer:

An Australian scientist by the name of John O'Sullivan was inspired by Stephen Hawking's theory of evaporating black holes and their subsequent radio waves. He set out to find them and prove the theory correct. (Wi-Fi was discovered on accident)

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What do you mean by data sequencing​
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Data sequencing is the sorting of data for inclusion in a report or for display on a computer screen.

Explanation:

8 0
3 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
1.
Brums [2.3K]

Answer:

as

is so good

Explanation:

7 0
3 years ago
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