PLEASE HELPP!!!!!!!!!

Two balls of equal size are dropped from the same height from the roof of a building. One ball has twice the mass of the other.

frutty [35]

Answer:

The kinetic energy of the more massive ball is greater by a factor of 2.

Explanation:

By conservation of energy, we know that the initial energy = final energy. At first, the balls are dropped from a height with no initial velocity so their initial energy is all potential energy. When they reach the bottom, all their energy is kinetic energy. So all of their energy is changed from potential to kinetic energy. This means that the ball with greater potential energy will have a greater kinetic energy.

Potential energy = mgh. Since g = gravity is a constant and h = height is the same, the only difference is mass. Since mass is directly proportional to potential energy, the greater the mass, the greater the potential energy, so the more massive ball has a greater initial potential energy and will have a greater kinetic energy at the bottom.

Additionally, let B1 = lighter ball with mass m and let B2 = heavier ball with mass m2. Since we know that intial potential energy = final kinetic energy. We can rewrite it as potential energy = kinetic energy = mass * gravity constant * height. For B1, it is mgh and for B2 it is 2mgh, so B2's kinetic energy is twice that of B1.

3 0

3 years ago

I WILL MAKE U BRAINLIEST PLEASE ANSWER !!!!!!!!

Nesterboy [21]

Answer:

125÷2= 62.5 is your average speed. If the train was resting it's not moving your going nowhere . If the train is traveling at constant speed in a straight line it's speed will increase going through mountains will slow it down. if the train is coming to a braking force its speed will decrease

3 0

3 years ago

If a student connects two resistors to a circuit parallel would the total resistance increase, decrease or does it not change an

OverLord2011 [107]

The total resistance would decrease

8 0

4 years ago

A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the forc

mel-nik [20]

Answer:

The coefficient of friction is (F/(19.6·m)

Explanation:

The given parameters are;

The force applied to the immovable body = F

The time duration the force acts = t

The time the body spends in motion = 3·t

The acceleration due to gravity, g = 9.8 m/s²

From Newton's second law of motion, we have;

The impulse of the force = F × t = m × Δv₁

Where;

Δv₁ = v₁ - 0 = v₁

The impulse applied by the force of friction, $F_f$ is $F_f$ × (3·t - t) = $F_f$ × (2·t)

Given that the motion of the object is stopped by the frictional force, we have;

The impulse due to the frictional force = Momentum change = m × Δv₂ = $F_f$ × (2·t)

Where;

Δv₂ = v₂ - 0 = v₂

Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to act, v₁, we have;

m × Δv₂ = $F_f$ × (2·t) = m × Δv₁ = F × t

∴ $F_f$ × (2·t) = F × t

$F_f$ = F × t/(2·t) = F/2

The coefficient of dynamic friction, $\mu _k$ = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)

$\mu _k$ = (F/(19.6·m)

The coefficient of friction, $\mu _k$ = (F/(19.6·m)

5 0

3 years ago

A mountain climber of mass 60.0 kg slips and falls a distance of 4.00 m, at which time he reaches the end of his elastic safety

Sever21 [200]

The energy that the rope absorbs from the climber is Ep=m*g*h where m is mass of the climber, g=9.81m/s² and h is the height the climber fell. h=4 m+2 m because he was falling for 4 meters and the rope stretched for 2 aditional meters. The potential energy stored in the rope is Er=(1/2)*k*x², where k is the spring constant of the rope and x is the distance the rope stretched and it is
x=2 m. So the equation from the law of conservation of energy is:

Ep=Er

m*g*h=(1/2)*k*x²

k=(2*m*g*h)/x² = (2*60*9.81*6)/2² = 7063.2/4 =1765.8 N/m

So the spring constant of the rope is k=1765.8 N/m.

7 0

3 years ago