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3 years ago

Express each of the following as indicated:

1 answer:

4 0

1 decimeter is equal to 100 millimeters. In this case, 2 decimeters is equal to 200 millimeters. 1 hour is equal to 3600 seconds while 1 minute is equal to 60 seconds. In this case, 2 h 10 minutes is equal to 7800 seconds. 1 gram is equal to 1000 micrograms. Thus, 16 grams is equal to 16000 mg and 0.675 mg is equal to 0.000675 grams. 1 centimeter is equal to 10000 micrometers. Hence 462 micrometers is equal to 0.0462 centimetes. 35 meter per hour is equal to 0.009722 m/s

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If the ultraviolet photon has a wavelength of 249 nm and one of the photons emitted by the fluorescent material has a wavelength

melamori03 [73]

Answer:

601 nm

Explanation:

Energy of photon having wavelength of λ nm

= $\frac{1244}{\lambda}$ eV

Energy of 249 nm photon

= $\frac{1244}{249}$

=4.996 eV

Similarly energy of 425nm photon

= $\frac{1244}{425}$

=2.927 eV

Difference = 2.069 eV.

This energy will give rise to another photon whose wavelength will be

λ = $\frac{1244}{2.069}$

= 601 nm.

6 0

4 years ago

Which of the following would be the best name for MgCl2?

Juliette [100K]

MgCl2 is magnesium chloride.
Hope this helps!

8 0

4 years ago

Read 2 more answers

7.According to the periodic table, how many total particles are there in the nucleus of a Titanium, Ti, atom?

FromTheMoon [43]

Answer:

there are 22 massive, positively charged, fundamental particles in the element's nucleus. Given this, the element is unquestionably titanium.

3 0

3 years ago

4 Points

lbvjy [14]

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method it is based on the principle of momentum and the amount of movement; and used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

$N*S=(kg*m/s^{2} )*s = kg*m/s$

Now replacing the values on the following equation that express the definition of impulse

$Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]$

4 0

3 years ago

Read 2 more answers

A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of re

slava [35]

The relationship between the resistance R of a wire and its resistivity $\rho$ is given by
$R= \frac{\rho L}{A}$
where L is the length of the wire and A is its cross sectional area.

In the problem, we have $R=0.5 \Omega$ , $\rho = 1.68 \cdot 10^{-8} \Omega m$ and $L=841 m$ . So we can solve the find the area A:
$A= \frac{\rho L}{R}=2.83 \cdot 10^{-5} m^2$

For a cylindrical wire, the cross sectional area is given by
$A= \pi r^2$
where r is the radius. We know the value of the area A, so now we can find the radius of the wire:
$r= \sqrt{ \frac{A}{\pi} }= \sqrt{ \frac{2.83 \cdot 10^{-5}m^2}{\pi} }=0.003 m=3.0 mm$

3 0

3 years ago