(a) 120.8 m/s^2
The gravitational acceleration at a generic distance r from the centre of the planet is

where
G is the gravitational constant
M' is the mass enclosed by the spherical surface of radius r
r is the distance from the centre
For this part of the problem,

so the mass enclosed is just the mass of the core:

So the gravitational acceleration is

(b) 67.1 m/s^2
In this part of the problem,

and the mass enclosed here is the sum of the mass of the core and the mass of the shell, so

so the gravitational acceleration is

Answer:
<h2>Letter which represent the resistance in this circuit diagram is</h2><h2>D</h2>
Explanation:
Here in this circuit diagram we know that
A = Battery
B = switch
C = connecting Wire
D = Resistance
This zig zag shape is represented as Resistance in all circuits
Chloroplast...................
Answer:
(C) speed = 40 m/s, distance = 80 m
Explanation:
According to Newton law of motion for a falling body:
v = u + gt
Where v is the final velocity, u is the initial velocity, t is the time taken to fall and g is the acceleration due to gravity.
Given that: t = 4 s, g = 10 m/s², u = 0 m/s(at top of building). Therefore substituting values:
v = 0 + 10(4)
v = 40 m/s
To find the distance h, we use the formula:
v² = u² + 2gh
Substituting values:
40² = 0² + 2(10)h
20h = 40² - 0²
20h = 1600
h = 1600 / 20
h = 80 m
The speed = 40 m/s, distance = 80 m
d = total displacement of the person running due east = 15 km
t = time taken by the person to travel the given distance due east = 2.0 hr
v = average velocity of the person in east direction = ?
average velocity is the ratio of total displacement to total time taken. hence
average velocity = total displacement/total time
v = d/t
inserting the values
v = 15 km/2.0 hr
v = 7.50 km/hr