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irina [24]
3 years ago
12

15 POINTS PLEASE PLEASE HELP ME!!

Physics
1 answer:
abruzzese [7]3 years ago
3 0
I will not help you but i would surely take these points for answering this question but i lied.
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A shot-putter projects the shot at 42.00˚ to the horizontal from a height of 2.100 m. It lands 17.00 m away horizontally. Next,
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Answer:

Explanation:

Let 100 m/s  be the velocity of projection.

So horizontal component

= 100 cos42

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Vertical component = - 100 sin 42 . in upward direction

66.91 m/s

Net displacement = 2.1 downwards ( + ve )

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2.1 = - 66.91 t  + .5 x 9.8 x t²

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t = 13.685 s

Horizontal distance covered

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= 100 cos40

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64.27 m/s

Net displacement = 2.1 downwards ( + ve )

Using s = ut + 1/2 gt²

2.1 = -76.60 t  + .5 x 9.8 x t²

4.9 t² -  76.60 t - 2.1 = 0

t = 15.659  s

Horizontal distance covered

= 15.659 x 76.60

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I can help, but

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