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3 years ago

How do I graph x is less than or equal to 4

1 answer:

7 0

First, graph the "equals" line, then shade in the correct area. There are three steps: Rearrange the equation so "y" is on the left and everything else on the right. or below the line for a "less than" (y< or y≤).

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Answer this question please and thank you

larisa86 [58]

Answer:

eight by eight is equals to sixty four

3 0

3 years ago

Which proportion could be used to find the length of side b?

Goshia [24]

Answer:

Step-by-step explanation:

Using the Sine Rule in ΔABC

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

∠C = 180° - (82 + 58)° = 180° - 140° = 40°

Completing values in the above formula gives

$\frac{a}{sin58}$ = $\frac{b}{sin82}$ = $\frac{8.4}{sin40}$

We require a pair of ratios which contain b and 3 known quantities, that is

$\frac{b}{sin82}$ = $\frac{8.4}{sin40}$

$\frac{sin40}{8.4}$ = $\frac{sin82}{b}$ → B

8 0

3 years ago

Read 2 more answers

Write nine and eighty-four hundredths in standard form.

Scrat [10]

The answer is: 9.84

4 0

3 years ago

Read 2 more answers

Convert 21/40 to a percent

Naya [18.7K]

21/40 = 52.50% (52.5)

5 0

4 years ago

Read 2 more answers

denis-greek [22]

Answer:

Part a) $AB=15\ cm$

Part b) $AB=11.1\ cm$

Part c) $AB=3/5\ cm$

Part d) $AB=3s\ cm$

Step-by-step explanation:

see the attached figure to better understand the question

we know that

To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor

Part a) we have

The scale factor is 5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(5)=15\ cm$

Part b) we have

The scale factor is 3.7

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(3.7)=11.1\ cm$

Part c) we have

The scale factor is 1/5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(1/5)=3/5\ cm$

Part d) we have

The scale factor is s

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(s)=3s\ cm$

7 0

3 years ago