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balu736 [363]
3 years ago
10

Gym class of 30 boys and 45 girls is divided into groups each group has the same number of students each group has only boys or

girls which is the greatest possible group sizes if every student participates
Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0
The greatest number of groups is 15. This is because 15 is a common multiple of 30 and 45
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Help I’ll give you 30 points
Gnesinka [82]

Answer:

a) 16.25 centimeters

b) 6.8 centimeters

Step-by-step explanation:

We can set up a proportion for both of these problems.

a) Look at the longest side of each triangle. We can set up a fraction: 7.2/18. We can also set up a fraction for XZ and PR:

6.5/x

x represents the length you're trying to find.

Since the triangles are similar, we have an equation:

7.2/18=6.5/x

Cross multiply

16.25

XZ is 16.25 centimeters long.

b)

We can do same thing:

7.2/18=x/17

Cross multiply

6.8

QR is 6.8 centimeters long.

Hope this helps!

6 0
3 years ago
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You should expect 28 defected cars.
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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

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Answer: I can give you the volume: 480. But to find the area I need more context to know which are the length and width.

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