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mamaluj [8]
3 years ago
9

Does -20 belong in whole numbers

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
Oh Yes It Does Yes It dose
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Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship
yan [13]

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

6 0
1 year ago
Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?
Korvikt [17]

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

6 0
3 years ago
Read 2 more answers
Solve the system of equations:
Simora [160]

Answer:

x1=6 , x2=1

Step-by-step explanation:

If you have any questions about the way I solved it,don't hesitate to ask

8 0
3 years ago
The height of a distance marker is 8 2/13 feet. 4/5 of the pole is painted white and rest is painted blue. How much of the pole
Mashcka [7]
1) Convert the mixed number 8 and 2/13 into a fraction:

8 and 2/13 = 8 + 2/13 = (8*13 + 2) / 13 = 106 / 13

2) Calculate 4/5 of 106 / 13

(4 / 5) * ( 106 / 13) = (4*106) / (5*13) = 424 / 65

That is (390 + 34) / 65 = 390/65 + 34/65 = 6 + 34/65 is painted white

3) Calculate the rest

 (1/5) * (106 / 13) = 106 / 65 = 1 + 41/65 is painted blue


6 0
3 years ago
If XY=18, YZ=14, and XZ=20, find the radius of each circle.
Pachacha [2.7K]
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P  are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P  + Y M = 18 X P - M Z  = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6  /* ( - 1 )X P  - M Z = 4 X P + Y M = - 6  X P - M Z = 4    Y M - M Z = - 2           Y M + M Z = 14            2 Y M = 12  =>  Y M = 6M Z - 6 = 2  =>   M Z = 8X P + 6 = 18 
 X P = 12
Radii of the circles are: 12, 8 and 6. 
8 0
3 years ago
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