Question

Five times the smallest of three consecutive odd integers is seven more than twice

Answer 1

Answer:

5, 7, 9

Step-by-step explanation:

Using the information given we get:

$5x-7=2z$

$x+2=y\\y+2=z\\x+4=z$

$5x-7=2(x+4)\\5x-7=2x+8$

Add 7 to both sides

$5x=2x+15$

Subtract 2x from both sides

$3x=15$

Divide both sides by 3

$x=5$

Using these equations:

$x+2=y\\y+2=z\\x+4=z$

and

$x=5$

We get:

$x=5\\y=7\\z=9$