Write the equation of the line in fully simplified slope-intercept form??

Mathematics

1 answer:

Elis [28]3 years ago

4 0

Answer:

y=-2/3x+3

Step-by-step explanation:

(m)slope :rise over run

(b)y-intercept :where the line crosses the y axis

slope intercept for y=mx+b

You might be interested in

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

olga nikolaevna [1]

$\ln x$ is continuous over its domain, all real $x>0$ .

Meanwhile, $\cos^{-1}y$ is defined for real $-1\le y\le1$ .

If $y=\ln x$ , then we have $-1\le \ln x\le1\implies \dfrac1e\le x\le e$ as the domain of $\cos^{-1}(\ln x)$ .

We know that if $f$ and $g$ are continuous functions, then so is the composite function $f\circ g$ .

Both $\cos^{-1}y$ and $\ln x$ are continuous on their domains (excluding the endpoints in the case of $\cos^{-1}y$ ), which means $\cos^{-1}(\ln x)$ is continuous over $\dfrac1e$ .

7 0

3 years ago

Can I please get help with this?

Andrei [34K]

Answer: x = 20.

Step-by-step explanation:

x and (3x + 10) combine to form a right angle, shown in the diagram by the small square joining the perpendicular lines.

Right angles are 90 degrees, so you can add both angles to get 90:

$x + (3x + 10) = 90\\\\4x + 10 = 90\\\\4x = 80\\\\x = 20$