I need help! Please..It's easy for u but hard for meh.

Mathematics

2 answers:

Katarina [22]2 years ago

4 0

For the first box it is 64 and for the second box it is 96

hichkok12 [17]2 years ago

4 0

All you need to do is find the unit rate by dividing 32 ➗ 3, and you get a unit rate of 10 2/3. Next, multiply 10 2/6 by 6 and 9 and you can find your answer.

I did not tell you the answer but I hope this helps you figure it out

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What is the equation of the line that passes through (-5, 0) and (4, 3)?

kotegsom [21]

Answer:

y = 1/3x + 5/3

Step-by-step explanation:

An equation contains a slope and y-intercept, in the form y = mx + b. To find the slope or m, you need to plug the coordinates into the slope formula.

y2 - y1/ x2 - 1

3 - 0/ 4 - (-5)

= 3 / 9

= 1/3

Now that we know the slope, we need to plug the values of x and y to find the y-intercept.

y = 1/3x + b

3 = 1/3(4) + b

3 = 4/3 + b

5/3 = b

The equation is y = 1/3x + 5/3

3 0

2 years ago

Solve for x each is a parallelogram

jonny [76]

Answer:

UW = EW+UE=2×EW because, EW=UE

7x-2=2×6= 12

7x=14

x=14/7

x=2

<h2>2 is the right answer.</h2>

x + 80 = 180 - (64 + 36)

x + 80 = 180 - 100

x + 80 = 80

x = 0

<h2>0 is the right answer.</h2>

3 0

2 years ago

The production manager is going to present this information to the company's board of directors. Which graph should the manager

viktelen [127]

To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):

If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.

Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.

Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.

Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.