Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price
![= \sum x.P(X=x)\\\\ = 1000 * 0.2 + 200 * 0.5 + 0 = \$ 300](https://tex.z-dn.net/?f=%3D%20%5Csum%20x.P%28X%3Dx%29%5C%5C%5C%5C%20%3D%201000%20%2A%200.2%20%2B%20200%20%2A%200.5%20%2B%200%20%3D%20%5C%24%20300)
Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.
There are 3 possible outcomes of each game.
So, the tree will start with 3 leaves, and each leaf will further be divided into 3 leaves. Thus the total number of leaves in the tree diagram will be 3 x 3 = 9 leaves.
Option A correctly represent this situation.
Answer:
X< 7/12
Step-by-step explanation:
Answer:
237 pounds
Step-by-step explanation:
237 pounds