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3 years ago

If x/y

Mathematics

1 answer:

Cloud [144]3 years ago

3 0

Answer:

B) No; because x and y could have a common irrational factor.

Step-by-step explanation:

The above answer speaks for itself.

An example is (√27)/(√3) = 3, the ratio of two irrational numbers with a common irrational factor.

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My question is the temperature one. Plz help me with one I'm stumped.

nikdorinn [45]

Isn't it 6 hoirs with the same temperature.?

7 0

3 years ago

The sales tax for an item was $19.20 and it costs $480 before tax. Find the sales tax rate. Write your answer as a percentage

Zigmanuir [339]

Answer:

sales tax rate = 4%

Step-by-step explanation:

In this problem formula to express one term in percentage is used

To express x as percentage of y is given by (x/y*100) %

______________________________________________

Cost of item = $480

sales tax = $19.20

we have to find sales tax rate.

sales tax rate is percentage of cost price which will levied as tax .

thus, we have to find sales tax as percentage of cost price.

using the percentage cost as given above

sales tax as percentage = sales tax/ cost of item *100

sales tax as percentage = 19.20/480 *100 = 4%

Thus, sales tax rate is 4%.

It means that if cost price of item is $100 then $4 will be the sales tax for the item.

5 0

3 years ago

A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

3 0

3 years ago

A 12 sided number cube with the numbers 1 through 12 is rolled.Select from the drop down menu to correctly complete the statemen

ioda

The 12 sided cube with the numbers 1 to 12 is rolled. That means it can land on any number from 1 to 12. The number of total possible outcomes is 12. The number of favourable outcomes, that is, the number of times the cube lands on a number than 4 is 12-1=11.
Probability=Number of favourable outcomes/number of total possible outcomes
= 11/12
= 0.92
I really hope this helps! And pls mark it as brainliest.

8 0

3 years ago

Sole for |p+8| over 2 =5

Lubov Fominskaja [6]

Answer:

p =2 p=-18

Step-by-step explanation:

|p+8|

-------------- = 5

Multiply each side by 2

|p+8|

-------------*2 = 5*2

|p+8| =10

There is a positive and a negative solution

p+8=10 p+8=-10

Subtract 8 from each side

p+8-8=10-8 p+8-8=-10-8

p =2 p=-18

7 0

4 years ago