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Alexxandr [17]
3 years ago
12

2995 divided by 27 but estimated

Mathematics
2 answers:
Vinil7 [7]3 years ago
6 0

Answer: 110

Step-by-step explanation:

aliina [53]3 years ago
6 0

Answer:

110.925925926

Step-by-step explanation:

Hope to help

greetings from Peru

and I don't know English XD

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rusak2 [61]

Answer:

D.4

Step-by-step explanation:

The y-intercept is where the line crosses the y-axis. This line crosses the y-axis at 4, or the point (0,4) so the y-intercept would be 4.

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3 years ago
Gail baked some muffins. She sold 2/7 of the muffins on Monday. She sold 1/3 more of the muffins on Tuesdays than on Monday. Wha
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13/21 were sold on the two days
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 Can someone plz help me What is the surface area of the figure?     A. 408 ft2   B. 458 ft2   C. 545 ft2   D. 720 ft2
AveGali [126]
There are 2 faces 7 x 5

2*(5*7)=2*35=70ft^2

There 2 faces 5 x 5

2*(5*5)=2*25=50ft^2

there are 3 faces 5 x 12

4*(5*12)=4*60=240ft^2

There are 2 faces 7 x 7

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Now only we have to sum all of them together

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6 0
4 years ago
Read 2 more answers
An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co
Blizzard [7]

Answer:

(a) C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2

    p(x)=320-7.7p

    R(x)=(320-7.7p)p=320p-7.7p^2

(b) x=82 \text{planes}

(c) p=\$30.91 M\;\; \text{per plane}

(d) maximum profit =\$ 15.90M

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

m(x)=20x-5x^{\frac{3}{4}}+0.01x^2

(a)  Find the cost, demand (or price), and revenue functions.

   C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2

   p(x)=320-7.7p

   R(x)=(320-7.7p)p=320p-7.7p^2

(b)  Find the production level that maximizes profit.

    f=R(x)-C(x)

 \Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)

\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx

     x=320-7.7p

     p=\frac{320-x}{7.7}

    \frac{dp}{dx} = \frac{-1}{7.7}

\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0

    \Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0

   \Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0

   \Rightarrow x=82 \text{planes}

(c)  Find the associated selling price of the aircraft that maximizes profit.

  p=\frac{320-82}{7.7}

\Rightarrow p=\$30.91 M\;\; \text{per plane}

(d)  Find the maximum profit.

Manufacturing cost of one plane is:

m(1)=20-5+0.01

         =\$15.01 M

maximum profit =\$(30.91-15.01)M

                           =\$15.90M

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3 years ago
What does 12*12= <br> its for a paper
Vlada [557]
Hey there! 12*12=144. Hope I helped! :)
5 0
4 years ago
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