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3 years ago

What is the net force acting on a falling object when it reaches terminal velocity?

Physics

2 answers:

valentinak56 [21]3 years ago

7 0

Answer:

Net force = 0

Explanation:

An object reaches its terminal velocity when the air resistance or drag force becomes equal to the weight of falling object. In this condition, the object is moving with constant speed.

And we know that acceleration, a = rate of change of velocity

If v = constant, then acceleration of an object is 0. Net force acting on an object is given by the product of its mass and acceleration as per Newton's second law i.e.

$F_{net}=ma$

So, $F_{net}=0$

Hence, net force acting on a falling object when it reaches terminal velocity is zero.

Nesterboy [21]3 years ago

6 0

I believe the answer is 0 because the force of air resistance equals the weight of the object.

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cupoosta [38]

Answer:

<h3>The answer is 1.92 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 2.5 g

Volume = 1.3 cm³

We have

$density = \frac{2.5}{1.3} \\ = 1.923076...$

We have the final answer as

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3 years ago

A spherical object (with non-uniform density) of mass 16 kg and radius 0.22 m rolls along a horizontal surface at a constant lin

Lapatulllka [165]

Answer:

Kr = 0.7618K

Explanation:

Suppose that the object's velocity is V, then his kinetic energy is:

K = $\frac{mv^{2} }{2}$

K = $\frac{(16)v^{2} }{2}$

K = 8 $v^{2}$

The rotational kinetic energy is

Kr = $\frac{Iw^{2} }{2}$

where I: The moment of inertia

ω: angular velocity

Kr = $\frac{(0.59)w^{2} }{2}$

Kr = 0.295 $w^{2}$

How the movement is without slipping, then

ω = $\frac{v}{r}$

ω = $\frac{v}{0.22}$

Thus

Kr = $\frac{0.295v^{2} }{0.22^{2} }$

Kr = 6.095 $v^{2}$

8 $v^{2}$ ----> 1

6.095 $v^{2}$ ----->?

Kr = 0.7618K

4 0

4 years ago

(1-dimension) A fish has a mass of 6 kg and is moving at a speed of 4m/s to the right. What is its momentum?

artcher [175]

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 6 × 4

We have the final answer as

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3 years ago

An electric motor rotating a workshop grinding wheel at a rate of 1.31 ✕ 102 rev/min is switched off. Assume the wheel has a con

antoniya [11.8K]

(a) 4.03 s

The initial angular velocity of the wheel is

$\omega_i = 1.31 \cdot 10^2 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=13.7 rad/s$

The angular acceleration of the wheel is

$\alpha = -3.40 rad/s^2$

negative since it is a deceleration.

The angular acceleration can be also written as

$\alpha = \frac{\omega_f - \omega_i}{t}$

where

$\omega_f = 0$ is the final angular velocity (the wheel comes to a stop)

t is the time it takes for the wheel to stop

Solving for t, we find

$t=\frac{\omega_f - \omega_i }{\alpha}=\frac{0-13.7 rad/s}{-3.40 rad/s^2}=4.03 s$

(b) 27.6 rad

The angular displacement of the wheel in angular accelerated motion is given by

$\theta= \omega_i t + \frac{1}{2}\alpha t^2$

where we have

$\omega_i=13.7 rad/s$ is the initial angular velocity

$\alpha = -3.40 rad/s^2$ is the angular acceleration

t = 4.03 s is the total time of the motion

Substituting numbers, we find

$\theta= (13.7 rad/s)(4.03 s) + \frac{1}{2}(-3.40 rad/s^2)(4.03 s)^2=27.6 rad$

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3 years ago

Question 1(Multiple Choice Worth 2 points)

tia_tia [17]

Answer:

Explanation:

the reason for each column is to show the electronic configuration of the elements in that column.

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3 years ago