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dimaraw [331]
3 years ago
9

Which of the following transfers energy in the form of vibrating electric and magnetic fields? A. An electromagnet B. A generato

r C. An induced current D. An electromagnetic wave
Physics
2 answers:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

D) An electromagnetic wave

Explanation:

Electromagnetic waves are a form of energy which will consist several parts as per the frequency range.

In all type of electromagnetic waves electric field and magnetic field is present which will oscillate perpendicular planes to each other.

here both electric field and magnetic field oscillates perpendicular to the direction of propagation of electromagnetic waves

here different parts of electromagnetic waves in order of increasing frequency range is given as

1. Radio waves

2. Microwaves

3. Infrared waves

4. Visible Light

5. Ultraviolet waves

6. X rays

7. Gamma Rays

All above electromagnetic waves have vibrating electric field and magnetic field perpendicular to each other and store energy in it.

user100 [1]3 years ago
3 0
Electromagnetic wave
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\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is R_{Eq}=2.00 \Omega, and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   =  \frac{5}{R}
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So, each piece of wire has a resistance of 10 \Omega. Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
R_{Eq}=R_1 + R_2 + ...+R_n
So if we apply it at our case, we have
R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega

therefore, the resistance of the original wire was 50 \Omega.
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