Static electricity is a ____ charge. missing temporary flowing permanent

Explain the phenomenon and change in potential energy

Reptile [31]

Answer:

Plz mark brainliest

Explanation:

As with kinetic energy, potential energy can change. When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the other object.

8 0

3 years ago

A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What

RSB [31]

V_2' = v_1 + v_1'
So v_2' = 40 + -25
We have set east to be + and west -
Which gives us 15 m/s. So thats how fast the 6 kg object is going.
This is true for an elastic collision.

4 0

3 years ago

At a fabrication plant, a hot metal forging has a mass of 75kg and a specific heat capacity of 430 J/(kg.C°). Toharden it, the f

zzz [600]

Answer:

The initial temperature of the metal is = 938.63 °C

Explanation:

Heat lost by the metal = heat gained by the oil.

c₁m₁(T₁-T₃) = c₂m₂(T₃-T₂)................ equation 1

making T₁ the subject of the equation.

T₁ = [c₂m₂(T₃-T₂) + c₁m₁T₃]/c₁m₁.............. Equation 2

Where c₁ = specific heat capacity of the metal, m₁ = mass of the metal, c₂ = specific heat capacity of oil, m₂ = mass of oil, T₁ = initial temperature of the metal, T₂ = initial temperature of the oil, T₃ = Equilibrium temperature.

Given: c₁ = 430 J/kg.°C, m₁ = 75 kg, c₂ = 2700 J/kg.°C, m₂ = 710 kg, T₂ = 32°C, T₃ = 47 °C

Substituting These values into equation 2,

T₁ = [2700×710×(47-32) + 430×75×47]/(430×75)

T₁ = (28755000+1515750)/32250

T₁ = 30270750/32250

T₁ = 938.63 °C

Thus the initial temperature of the metal is = 938.63 °C

7 0

3 years ago

Why are objects that fall near earths surface rarely in free fall?

marissa [1.9K]

"Free fall" means that gravity is the ONLY force acting on the object. If there's air resistance, then it isn't free-fall.

Objects that fall near earths surface are ALWAYS falling through air, unless they're inside some kind of a vacuum chamber with all the air removed from it.

8 0

3 years ago

Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.

Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

$f=\frac{R}{2}$

For this mirror, R = 20 cm, so its focal length is

$f=\frac{20}{2}=+10 cm$ (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm$

b)

We can solve this part by using the magnification equation:

$M=-\frac{y'}{y}=\frac{q}{p}$

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

$y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm$

and the negative sign means that the image is inverted.

#LearnwithBrainly

6 0

3 years ago