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Tanzania [10]
2 years ago
6

Static electricity is a ____ charge. missing temporary flowing permanent

Physics
1 answer:
adoni [48]2 years ago
6 0

Answer:

static electricity is a flowing charges

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A space station that does not rotate cannot simulate gravity for its occupants.
il63 [147K]

false

true

false

false

true

4 0
3 years ago
A 7.91g bullet is fired into a 1.52-kg ballistic pendulum initially at rest and becomes embedded in it. The pendulum subsequentl
Stella [2.4K]

Answer:

D

Explanation:

By law of conservation of momentum:

momentum before collision = momentum after collision

m_{1} u_1 + m_2 u_2  = m_1 v_1 + m_2  v_2\\ m_1 = mass of bullet\\u_1 = initial speed of bullet\\m_2 = mass of pendulum\\u_2 = initial speed of pendulum\\v_1 = final speed of bullet\\v_2 = final speed of pendulum

Initial speed of bullet is unknown whereas initial speed of pendulum will be zero as it was at rest.

Final speed of bullet and pendulum will be equal as bullet is embedded in pendulum and both moves together a vertical distance of 6.89cm.

Using third equation of motion:

2 a S = v_{f}^2  - v_{i}^2

where:

a = -g = acceleration due to gravity = 9.8 m/s^2 ( for vertical motion)\\S = h = 6.89cm = Vertical height or distance it covers\\v_f = final speed = 0 (after covering 6.89cm)\\v_i = initial speed (unknown)

Thus by placing values v_i = 1.1620 m/s

this speed will be final speed of collision for the calculation of initial speed of bullet.

Putting values:

(7.91) * x + (1.52*10^3) * 0 = (7.91 + 1.52*10^3) * 1.162\\7.91 x = 1775.431\\x = 224m/s

This 224m/s = 0.224Km/s which is closest to D

8 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy ne
Allisa [31]

Answer:

17 * 10^5 J

Explanation:

From;

H= mcΘ

where;

m = mass of water = 5.0 Kg

c = heat capacity of water = 4 200 J/Kg °C

Θ = temperature rise = 100 °C - 20 °C = 80°C

Substituting values;

H = 5 * 4 200 * 80

H = 17 * 10^5 J

4 0
3 years ago
A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
galina1969 [7]

Answer:

Force on the proton will be .73\times 10^{-14}N

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light c=3\times 10^8m/sec

So speed of proton v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec

Magnetic field B = 0.00629 T

Charge on proton q=1.6\times 10^{-16}C

Angle between velocity and magnetic field \Theta =137^{\circ}

Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

4 0
3 years ago
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