Answer:
40 m/s North
Explanation:
m = 10 kg
u = 4 m/s North = 4 j
m1 = 5 kg
v1 = 8 m/s west = - 8 i
m2 = 4 kg
v2 = 10 m/s east = 10 i
m3 = m - m1 - m2 = 10 - 5 - 4 = 1 kg
Let the velocity of third fragment is v3 = v
Using the conservation of momentum
m x u = m1 x v1 + m2 x v2 + m3 x v3
10 x 4 j = 5 x (- 8i) + 4 x 10 i + 1 x v3
40 j = - 40 i + 40 i + v3
v3 = 40 j
Thus, the third fragment moves in the direction of north with velocity 40 m/s
Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
n=162500000 t
The number of electron passe per second will be 162500000.
Answer:
energy
Explanation:
waves can move distances without transferring any matter, so the answer is energy