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4 years ago

11

During the early 1800s, these professionals regularly appeared in court to answer questions related to physical evidence.

2 answers:

-Dominant- [34]4 years ago

8 0

Answer: Forensic science

In early 1800s, the professional investigators regularly attend court trial to answer questions related to physical evidence, which is described as forensic science. The study of physical evidence is a practical tool to assist police in conducting investigations by developing a sense of how the crime was committed. Therefore, the application of forensic science is a great help in solving crime.

ivolga24 [154]4 years ago

7 0

Forensic science is the answer

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A flight distance from philadelphia to cancun is 1469 miles.the estimated flight time is 3.25 hours.What is the avarage speeede

Jlenok [28]

Answer:

1469 miles /3.25 hours = 452 miles per hours

Explanation:

divide distance by the time it takes to get there

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3 years ago

A tiger leaps from a rock 15 meters off the ground with a horizontal velocity of 4.5m/s. How far away from the rock will the tig

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3 years ago

Water in an ice cube tray is put into the freezer section of a refrigerator. As it freezes, this water — A loses all entropy B i

Svetradugi [14.3K]

Answer:

<h2>Due to extraction of heat from the water the entropy of the water will decrease</h2><h2>so correct answer is</h2><h2>C decreases in entropy</h2>

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$\Delta S = \int{\frac{dQ}{T}}$

So here we know that initially in ice tray we put water at room temperature into this

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3 years ago

An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the

garik1379 [7]

(a) 6.04 rev/s

The speed of the ball is given by:

$v=\omega r$

where

$\omega$ is the angular speed

r is the distance of the ball from the centre of the circle

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$\omega=8.13 rev/s \cdot 2\pi = 51.0 rad/s$

r = 0.600 m

So the speed of the ball is

$v=(51.0 rad/s)(0.600 m)=30.6 m/s$

In situation 2), we have

$\omega=6.04 rev/s \cdot 2\pi = 37.9 rad/s$

r = 0.900 m

So the speed of the ball is

$v=(37.9 rad/s)(0.900 m)=34.1 m/s$

So, the ball has greater speed when rotating at 6.04 rev/s.

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The centripetal acceleration of the ball is given by

$a=\frac{v^2}{r}$

where

v is the speed

r is the distance of the ball from the centre of the trajectory

For situation 1),

v = 30.6 m/s

r = 0.600 m

So the centripetal acceleration is

$a=\frac{(30.6 m/s)^2}{0.600 m}=1561 m/s^2$

(c) $1292 m/s^2$

For situation 2 we have

v = 34.1 m/s

r = 0.900 m

So the centripetal acceleration is

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