All categories

4 years ago

During the early 1800s, these professionals regularly appeared in court to answer questions related to physical evidence.

Physics

2 answers:

-Dominant- [34]4 years ago

8 0

Answer: Forensic science

In early 1800s, the professional investigators regularly attend court trial to answer questions related to physical evidence, which is described as forensic science. The study of physical evidence is a practical tool to assist police in conducting investigations by developing a sense of how the crime was committed. Therefore, the application of forensic science is a great help in solving crime.

ivolga24 [154]4 years ago

7 0

Forensic science is the answer

You might be interested in

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance

larisa [96]

Answer:

R = 28.125 ohms

Explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

$R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega$

So, the resistance of the filament is equal to 28.125 ohms.

5 0

3 years ago

A motorboat travels 92 km in 2 hours going upstream. It travels 132 km going downstream in the same amount of time. What is the

taurus [48]

Answer:

The speed on boat in still water is $56 \frac{km}{h}$ and the rate of the current is $10 \frac{km}{h}$

Explanation:

Since speed , $v= \frac{Distance\, traveled(D)}{Time\, taken(t)}$

Therefore speed of motor boat while traveling upstream is

$v_{upstream}=\frac{92}{2}\frac{km}{h}=46\frac{km}{h}$

and speed of motor boat while traveling downstream is

$v_{downstream}=\frac{132}{2}\frac{km}{h}=66\frac{km}{h}$

Let speed of boat in still water be $v_b$ and rate of current be $v_w$

Therefore $v_{upstream}=v_b-v_w=46\frac{km}{h}$ ----(A)

and $v_{downstream}=v_b+v_w=66\frac{km}{h}$ ------(B)

Adding equation (A) and (B) we get

$2v_b= (46+66) \frac{km}{h}=112 \frac{km}{h}$

=> $v_b= 56 \frac{km}{h}$ ------(C)

Substituting the value of $v_b$ in equation (A) we get

$v_w= 10 \frac{km}{h}$

Thus the speed on boat in still water is $56 \frac{km}{h}$ and the rate of the current is $10 \frac{km}{h}$

5 0

4 years ago

a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien

Law Incorporation [45]

Answer:

The magnitude of the friction force is 8197.60 N

Explanation:

Using the definition of the centripetal force we have:

$\Sigma F=ma_{c}=m\frac{v^{2}}{R}$

Where:

m is the mass of the car
v is the speed
R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

$F_{f}=m\frac{v^{2}}{R}$

$F_{f}=2100\frac{18^{2}}{83}$

$F_{f}=8197.60 \: N$

Therefore the magnitude of the friction force is 8197.60 N

I hope it helps you!

7 0

3 years ago

If 4000 C of charge pass through a section of wire in 50 seconds, what would the current be?

9966 [12]

Answer:

Explanation:

Given that,

Charge through a wire is

Q = 4000C

Time for charge to pass through the wire is

t = 50seconds

Then,

Current through the wire is the rate of charge passing through the wire

Q = it

Where

Q is charge.

I is current

t is time taken

Therefore,

I = Q / t

I = 4000 / 50

I = 80 Amps

3 0

4 years ago

How do you calculate wave speed?

klasskru [66]

speedusing the v = f. λ equation.

4 0

3 years ago